AeroElectric-List Digest Archive

Tue 05/13/03


Total Messages Posted: 46



Today's Message Index:
----------------------
 
     1. 03:59 AM - Re: my other life (KITFOXZ@aol.com)
     2. 04:44 AM - Re: my other life (Beckman, Rick)
     3. 05:16 AM - Re: my other life (Alex Peterson)
     4. 05:29 AM - Mic Jack Wiring (Mark Nielsen)
     5. 05:59 AM - Re: Mic Jack Wiring (Rick Caldwell)
     6. 06:09 AM - Re: my other life (Robert L. Nuckolls, III)
     7. 06:18 AM - Re: my other life (Dennis O'Connor)
     8. 06:22 AM - Re: AutoPilot Disconnect (Mark Phillips)
     9. 06:27 AM - Re: AutoPilot Disconnect (Mark Phillips)
    10. 07:02 AM - Re: AutoPilot Disconnect (Shannon Knoepflein)
    11. 07:06 AM - Re: my other life (Robert L. Nuckolls, III)
    12. 07:09 AM - Re: AutoPilot Disconnect (Robert L. Nuckolls, III)
    13. 07:24 AM - Re: my other life (BobsV35B@aol.com)
    14. 07:39 AM - Re: my other life (Robert L. Nuckolls, III)
    15. 07:48 AM - Re: Mic Jack Wiring (Robert L. Nuckolls, III)
    16. 07:54 AM - Re: Tach P-lead feed (Vincent Welch)
    17. 08:37 AM - Re: AutoPilot Disconnect (Robert L. Nuckolls, III)
    18. 08:41 AM - Re: OV circuit breaker tripping (Robert L. Nuckolls, III)
    19. 09:01 AM - Re: Re: Flap system failure modes (Was circuit protection issues) (Phil Birkelbach)
    20. 09:55 AM - Re: AutoPilot Disconnect (Shannon Knoepflein)
    21. 10:09 AM - Re: AutoPilot Disconnect Brain Teaser - 05/12/03 (MikeM)
    22. 10:32 AM - Re: AutoPilot Disconnect (John Loram)
    23. 11:28 AM - Re: Re: AutoPilot Disconnect Brain Teaser - (Robert L. Nuckolls, III)
    24. 11:34 AM - Re: AutoPilot Disconnect (Robert L. Nuckolls, III)
    25. 11:43 AM - OV runaway in an internally regulated alternator (Robert L. Nuckolls, III)
    26. 12:05 PM - Re: OV circuit breaker tripping (JOHN KARNES)
    27. 12:06 PM - Re: Re: Flap system failure modes (Was circuit protection issues) (Gilles.Thesee)
    28. 12:06 PM - Re: Re: Flap system failure modes (Was circuit protection issues) (Gilles.Thesee)
    29. 01:03 PM - Re: Z13 and Dual Electronic Ignitions (Shaun Simpkins)
    30. 01:05 PM - Re: OV circuit breaker tripping (Cy Galley)
    31. 01:13 PM - Re: Re: AutoPilot Disconnect Brain Teaser - 05/12/03 (Phil Birkelbach)
    32. 03:49 PM - Re: Re: AutoPilot Disconnect Brain Teaser -05/12/03 (Robert McCallum)
    33. 04:33 PM - Re: Re: Flap system failure modes (Was (Robert L. Nuckolls, III)
    34. 04:33 PM - Re: Re: AutoPilot Disconnect Brain Teaser -05/12/03 (Carlos Sa)
    35. 05:11 PM - Re: Re: AutoPilot Disconnect Brain Teaser -05/12/03 (Robert McCallum)
    36. 05:52 PM - Re: Microprocessor based Fuel Gauge Linearizer (nhulin)
    37. 07:48 PM - Re: Re: AutoPilot Disconnect Brain Teaser (Robert L. Nuckolls, III)
    38. 07:53 PM - Re: Re: AutoPilot Disconnect Brain Teaser - (Robert L. Nuckolls, III)
    39. 07:57 PM - Re: OV circuit breaker tripping (Robert L. Nuckolls, III)
    40. 09:15 PM - Re: OV circuit breaker tripping (John Karnes)
    41. 09:15 PM - Re: Re: AutoPilot Disconnect Brain Teaser-05/12/03 (Robert McCallum)
    42. 09:24 PM - Fw: Electric Bob - Microair Radio-Xpdr Wire Harness (Rick Fogerson)
    43. 09:58 PM - Dual electronic ignition - revisited again (Geoff Evans)
    44. 10:03 PM - Re: OV circuit breaker tripping (Robert L. Nuckolls, III)
    45. 10:04 PM - Re: Fw: Electric Bob - Microair Radio-Xpdr (Robert L. Nuckolls, III)
    46. 10:05 PM - Re: Re: AutoPilot Disconnect Brain (Robert L. Nuckolls, III)
 
 
 


Message 1


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    Time: 03:59:30 AM PST US
    From: KITFOXZ@aol.com
    Subject: Re: my other life
    --> AeroElectric-List message posted by: KITFOXZ@aol.com $200 bucks? Wow Bob. You are definitely earning your keep. Didn't the boss want a tail rotor on it too? Some of us want you to burn a CD of it dancing around the yard. Does it have a name yet? How about the "Rotor Way Reject" J John P. Marzluf Columbus, Ohio Kitfox Outback (out back in the garage)


    Message 2


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    Time: 04:44:30 AM PST US
    From: "Beckman, Rick" <Rick.Beckman@atk.com>
    Subject: my other life
    --> AeroElectric-List message posted by: "Beckman, Rick" <Rick.Beckman@ATK.COM> Thought some of you might be interested in seeing what I'm doing in the shop for RAC right now. Just pushed this critter out into the yard for painting this afternoon. It's a centrifuge capable of putting 30G of linear acceleration on some of the equipment we're going to fly in a new super-sonic target (GQM-163) that flys mach 2+ at 15 feet off the water. Good job Bob!!!!!


    Message 3


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    Time: 05:16:37 AM PST US
    From: "Alex Peterson" <alexpeterson@usjet.net>
    Subject: my other life
    --> AeroElectric-List message posted by: "Alex Peterson" <alexpeterson@usjet.net> What happens if that sucker hits a bee or a dragonfly at mach 2??? Alex Peterson > > Thought some of you might be interested in seeing > what I'm doing in the shop for RAC right now. Just > pushed this critter out into the yard for painting > this afternoon. > > It's a centrifuge capable of putting 30G of linear > acceleration on some of the equipment we're going > to fly in a new super-sonic target (GQM-163) that > flys mach 2+ at 15 feet off the water. > > > http://216.55.140.222/temp/MVC-650X.JPG > http://216.55.140.222/temp/MVC-651X.JPG


    Message 4


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    Time: 05:29:14 AM PST US
    From: "Mark Nielsen" <mark.nielsen@fiedler-lp.com>
    Subject: Mic Jack Wiring
    --> AeroElectric-List message posted by: "Mark Nielsen" <mark.nielsen@fiedler-lp.com> Bob or anyone else, I have a question on Bob's shop notes on aircraft mic jack wiring ( <http://www.aeroelectric.com/articles/micjack/micjack.html> http://www.aeroelectric.com/articles/micjack/micjack.html). I am installing an Icom A200 comm radio. Pin 9 is the PTT switch; the pin is grounded to activate. The wiring for the Microair that Bob shows appears to be similar, and the PTT circuit is wired through the PTT terminal on the mic jack. My question, what happens at the mic jack/plug? Does the plug just complete the PTT circuit to ground? If so, would it also work if the jack/plug was taken out of the circuit? (Ground the PTT pin without wiring the PTT terminal at the jack.) Or Is the circuit needed to activate the headset mic? If so, what activates the mic when you are just using the intercom function? Mark Nielsen RV-6; 812 hrs.


    Message 5


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    Time: 05:59:40 AM PST US
    From: "Rick Caldwell" <racaldwell@hotmail.com>
    Subject: Re: Mic Jack Wiring
    --> AeroElectric-List message posted by: "Rick Caldwell" <racaldwell@hotmail.com> Mark, This is the "normal" way to wire the PTT. However, you do not need to wire it to the mic jack. But if you bypass it & go directly to the PTT switch, you can not use the portable PTT switch that plugs into the mic jack. The mic itself does not need this wired up. Rick Caldwell RV-6 & One Design > >I have a question on Bob's shop notes on aircraft mic jack wiring ( ><http://www.aeroelectric.com/articles/micjack/micjack.html> >http://www.aeroelectric.com/articles/micjack/micjack.html). I am >installing an Icom A200 comm radio. Pin 9 is the PTT switch; the pin is >grounded to activate. The wiring for the Microair that Bob shows appears >to be similar, and the PTT circuit is wired through the PTT terminal on >the mic jack. My question, what happens at the mic jack/plug? Does the >plug just complete the PTT circuit to ground? If so, would it also work >if the jack/plug was taken out of the circuit? (Ground the PTT pin >without wiring the PTT terminal at the jack.) > >Or > >Is the circuit needed to activate the headset mic? If so, what activates >the mic when you are just using the intercom function? > >Mark Nielsen > >RV-6; 812 hrs. > >


    Message 6


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    Time: 06:09:06 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: my other life
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 11:10 PM 5/12/2003 -0700, you wrote: >--> AeroElectric-List message posted by: Jaye and Scott Jackson ><jayeandscott@shaw.ca> > >What I want to know is where on Earth did you find the time? >Scott It's part of my job. The 40 hours I put into it have been spread out over several months. I also built a drop tower for shock testing these same pieces of equipment. By doing these tasks in my shop at home, I can nudge them along much more efficiently than if I had them built at RAC. For one thing, there are no drawings for these pieces of test equipment. To make a set of drawings from which someone else would build it might take 40 hours of overhead time just to make the drawings, get them checked and run through the release system. Then, if something didn't work out, the person building the fixture cannot make any changes to the design until revised drawings are released. By designing on the fly, I could take advantage of parts I found in hardware stores and make instant changes when things didn't come together as originally envisioned. RAC could have built it in-house but I suspect they would have invested about 2x the person-hours. As it stands now, RAC's total investment is about $3200. Bob . . .


    Message 7


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    Time: 06:18:46 AM PST US
    From: "Dennis O'Connor" <doconnor@chartermi.net>
    Subject: Re: my other life
    --> AeroElectric-List message posted by: "Dennis O'Connor" <doconnor@chartermi.net> Just a word to the wise, Bob... Will it work if nothing goes wrong? - Probably... But in my wasted youth I was around all kinds of machinery and to my eye you need a harness attached to that upper bearing block with four cables running out to ground anchors, and the base firmly anchored also... Also, the lower end of the shaft needs to be longer and set into another bearing or sleeve as the current setup will twist itself out of the plywood box if the brown stuff hits the fan...... You can use belt pulleys to run the drill motor from the side of the shaft... The other thing you need to plan for is containment of a part flying off... A battery makes a pretty good missile when flung off a 180 rpm Trebouchet... The slightest problem, such as the load slipping, a bearing seizing, a squirrel trying to dive through, etc. will turn that thing into a flail mower... You just never know with open frame, rotating machinery... Denny ya, ya, ya, I know - I'm just an old worry wart... ----- Original Message ----- From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> Subject: AeroElectric-List: my other life > --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> > > Thought some of you might be interested in seeing > what I'm doing in the shop for RAC right now. Just > pushed this critter out into the yard for painting > this afternoon. > > It's a centrifuge capable of putting 30G of linear > acceleration on some of the equipment we're going > to fly in a new super-sonic target (GQM-163) that > flys mach 2+ at 15 feet off the water. > > > http://216.55.140.222/temp/MVC-650X.JPG > http://216.55.140.222/temp/MVC-651X.JPG > > The big bucket holds test articles. The smaller > bucket holds batteries to power article under > test. The battery bucket can be moved along the > beam to coarse balance against the test article. > > A table mounts at the center of the beam to > hold control computer and telemetry to take > test signals off the centrifuge and control > signals on. > > I used boat trailer 1" wheel bearings I found > at Walmart. Turned a solid aluminum shaft to > mount beam, pass through bearings and accept > rotation torque from 1/2" drill motor underneath. > > Drill motor is about 10x oversized for task but > had nice handles that made it easy to incorporate > into the test fixture. It looks like something on > the order of 15 volts DC will spin this rig up to > about 3 revolutions per second to give me 30G in > the big bucket. > > The boss priced one of these and was quoted about > $18,000. I think I beat that price by a good margin! > I've got just over $200 in materials and about > 40 hours in it. > > > Bob . . . > > -------------------------------------------- > ( Knowing about a thing is different than ) > ( understanding it. One can know a lot ) > ( and still understand nothing. ) > ( C.F. Kettering ) > -------------------------------------------- > >


    Message 8


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    Time: 06:22:23 AM PST US
    From: Mark Phillips <ripsteel@edge.net>
    Subject: Re: AutoPilot Disconnect
    --> AeroElectric-List message posted by: Mark Phillips <ripsteel@edge.net> > http://216.55.140.222/temp/AP_Disconnect_B.pdf > > Here's a brain teaser for you electro-wienies out there. Oh goodie- another chance to publicly expose my ignorance! 8-) > Why is a diode across the coil of the relay not only > not needed but would be ineffectual were it included? Collapsing field current goes to ground through the little switch > Why, if we can hook an autopilot motor of up to 5A > on this disconnect system, an itty-bitty stick-grip > engage/disengage switch good for perhaps 2A is sufficient? Servo motor current passes through the relay contact, not the relay activate switch which only carries relay coil current- which is why we use the things > Why can we get by with a 1w resistor when dissipation > in this resistor at 14v is nearly 20 watts? Coil inductance? Best a bigger wienie than me answer this one! By the way, shouldn't this switch be shown as (mom)-off-(mom)? Mark - do not archive -


    Message 9


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    Time: 06:27:03 AM PST US
    From: Mark Phillips <ripsteel@edge.net>
    Subject: Re: AutoPilot Disconnect
    --> AeroElectric-List message posted by: Mark Phillips <ripsteel@edge.net> I said: "shouldn't this switch be shown as (mom)off(mom)?" It is (duh)- that's what the little triangle shaped contacts mean--- too early to be trying this stuff! (sorry!) Mark - do not archive -


    Message 10


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    Time: 07:02:29 AM PST US
    From: "Shannon Knoepflein" <kycshann@kyol.net>
    Subject: AutoPilot Disconnect
    --> AeroElectric-List message posted by: "Shannon Knoepflein" <kycshann@kyol.net> The diode will be ineffectual because of the latch in resistor. This resistor will provide a means of dissipating the coils field current. Assuming the coil of the s704-1 is about 150 ohms, based on your statement of less than 100ma to engage, we get 150+10, or 160 ohms resistance from 14V to ground (once the engage switch is pressed). This computes to 87.5mA of current flow, hence a 2A switch is more than enough. The engage current is less than 100mA per the specs of the s704-1. The disengage current will be 14/10, or 1.4A, still within 2A. We can get by with the 1W resistor due to the current limiting of the coil resistance to under 100mA (~150 ohms). Adding the 10ohm resistor lowers the current further to about 87.5mA. The power dissipated in the resistor is I 2*R, or 87.5mA 2*10= 0.076W, well under the 1W rating. --- Shannon Knoepflein <---> kycshann@kyol.net -----Original Message----- From: owner-aeroelectric-list-server@matronics.com [mailto:owner-aeroelectric-list-server@matronics.com] On Behalf Of Robert L. Nuckolls, III Subject: Re: AeroElectric-List: AutoPilot Disconnect --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 01:26 PM 5/12/2003 -0600, you wrote: >--> AeroElectric-List message posted by: "Jim Pack" <jpack@igs3.com> > >In october last year a link was provided to an autopilot disconnect >schematic. The link was: > >http://216.55.140.222/temp/AP_Disconnect.pdf > >The link is dead, does anyone have a copy of the schematic? > >Thanks, >Jim The old one was replaced with a simpler version and posted at: http://216.55.140.222/temp/AP_Disconnect_B.pdf Here's a brain teaser for you electro-wienies out there. Why is a diode across the coil of the relay not only not needed but would be ineffectual were it included? Why, if we can hook an autopilot motor of up to 5A on this disconnect system, an itty-bitty stick-grip engage/disengage switch good for perhaps 2A is sufficient? Why can we get by with a 1w resistor when dissipation in this resistor at 14v is nearly 20 watts? Bob . . .


    Message 11


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    Time: 07:06:18 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: my other life
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 06:58 AM 5/13/2003 -0400, you wrote: >--> AeroElectric-List message posted by: KITFOXZ@aol.com > >$200 bucks? Wow Bob. You are definitely earning your keep. Didn't the boss >want a tail rotor on it too? Some of us want you to burn a CD of it dancing >around the yard. > >Does it have a name yet? How about the "Rotor Way Reject" J . . . that's a good one. Dee's favorite color is purple. I suggested we could name it the "Rolling Purple Parts Eater". But alas, I'm almost finished painting it the relatively standard shop-tool gray. Bob . . .


    Message 12


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    Time: 07:09:17 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: AutoPilot Disconnect
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 10:01 PM 5/12/2003 -0700, you wrote: >--> AeroElectric-List message posted by: John Loram <johnl@loram.org> > >This is fun; > >The first thing to know is that the relay's coil (S704-1) has a resistance >of greater than 140 ohms (base on Aeroelectric specs of, "coil current is >under 100 millamps [sic]"). yes >In the 'quiescent' state (no servo motor power) there is no current flowing >through either the coil or the resistor. yes >In the 'active' state (servo motor is powered) there is 14 volts to the top >of the 10 ohm resistor which flows through the resistor and the relay coil >to ground. This current is sufficient to hold the relay in the active >position, and is 14volts / (10 ohms + 140 ohms) = .092 amps (92 milliamps). >This produces .092ma >2 * 140ohms = 1.18 watts dissipation in the relay (it >will run warm) and .092ma >2 * 10 = 0.08 watts dissipation in the resistor. yes >During the transition state when the small switch is held in the 'engage' >position, 14 volts is applied directly across the relay coil, pulling the >relay into the 'active' state. yes, but assume you have a 5A load (2.5 ohms) load (servo motor) what is dissipation in resistor at time of engage switch closure and how long does it last? >During the transition state when the small switch is held in the 'disengage' >position, the junction between the 10 ohm resistor and the relay coil will >be held at ground. The current (92 milliamps) flowing through the relay coil >will flow through the small switch to ground, and the energy stored in the >relay coil's magnetic field will be dissipated in the coil's resistance. >There will be a brief spike of current (a bit over an amp) from the 10 ohm >resistor through the small switch. This current will stop as soon as the >relay's magnetic field falls to the point where the relay contacts open >(drops out). Okay, what is the dissipation in resistor at time of dis-engage switch closure and how long does it last? What is dissipation mode for energy stored in the relay coil? >(is there a prize????) ;-) -john- Sure, after you finish the test . . . Bob . . .


    Message 13


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    Time: 07:24:20 AM PST US
    From: BobsV35B@aol.com
    Subject: Re: my other life
    --> AeroElectric-List message posted by: BobsV35B@aol.com In a message dated 5/13/03 8:19:43 AM Central Daylight Time, doconnor@chartermi.net writes: > The slightest problem, such as the load slipping, a bearing seizing, a > squirrel trying to dive through, etc. will turn that thing into a flail > mower... You just never know with open frame, rotating machinery... > > Denny > > Good Morning Denny, Or you just put the whole shebang inside a suitable containment vessel, and let 'er rip! Happy Skies, Old Bob


    Message 14


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    Time: 07:39:06 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: my other life
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 09:18 AM 5/13/2003 -0400, you wrote: >--> AeroElectric-List message posted by: "Dennis O'Connor" ><doconnor@chartermi.net> > >Just a word to the wise, Bob... >Will it work if nothing goes wrong? - Probably... But in my wasted youth I >was around all kinds of machinery and to my eye you need a harness attached >to that upper bearing block with four cables running out to ground anchors, >and the base firmly anchored also... Also, the lower end of the shaft needs >to be longer and set into another bearing or sleeve as the current setup >will twist itself out of the plywood box There are bearings at both ends of the shaft, top and bottom of the bearing box. > if the brown stuff hits the >fan...... You can use belt pulleys to run the drill motor from the side of >the shaft... The other thing you need to plan for is containment of a part >flying off... A battery makes a pretty good missile when flung off a 180 rpm >Trebouchet... All good points. Keep in mind that for this thing to function with any degree of civility, it has to be carefully balanced. We have knife edge balance points at the center of the shaft flange. Everything on the moving frame has to be held down with hardware appropriate to the forces. Test articles and batteries are in the buckets . . . the batteries cannot move and test articles can't go very far . . . but even these are fastened in on brackets and hardware good for several times expected loads. Beam unbalance will be less than 0.1 oz-in. The beam and buckets are designed for stiffness. The I-beam is 5 x 5 with 5/16" webs. Friction at the bearings is quite low. You cannot touch the beam at the end lightly enough to keep it from rotating away from you. Acceleration forces will be so low for both increasing and decreasing speed that the base can sit in caster-cups. Buckets are 1/8" alum sheet riveted together with 1/8" angle at the corners. Force needed to seriously deflect these shapes is over 4,000 pounds. >The slightest problem, such as the load slipping, a bearing seizing, a >squirrel trying to dive through, etc. will turn that thing into a flail >mower... You just never know with open frame, rotating machinery... Yup, we've been doing this stuff for years. Just not on this scale. I had to build this fixture 'cause our existing rate table will only handle articles up to 2 pounds or so. We've studied and learned the need for robustness and attention to details. Even so, no person will be in the room with this thing operating. All the computer and control equipment needed to conduct the operation will be in zero-G land on a shelf in the center. Command and monitoring will be done by radio so we can set in the next room and know what's happening. Aside from weight (about 80#) and g-forces (#350 lb max), forces in the rest of the system are very low. Bob . . .


    Message 15


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    Time: 07:48:46 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: Mic Jack Wiring
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 07:29 AM 5/13/2003 -0500, you wrote: >--> AeroElectric-List message posted by: "Mark Nielsen" ><mark.nielsen@fiedler-lp.com> > >Bob or anyone else, > >I have a question on Bob's shop notes on aircraft mic jack wiring ( ><http://www.aeroelectric.com/articles/micjack/micjack.html> >http://www.aeroelectric.com/articles/micjack/micjack.html). I am >installing an Icom A200 comm radio. Pin 9 is the PTT switch; the pin is >grounded to activate. The wiring for the Microair that Bob shows appears >to be similar, and the PTT circuit is wired through the PTT terminal on >the mic jack. My question, what happens at the mic jack/plug? Does the >plug just complete the PTT circuit to ground? yes > If so, would it also work >if the jack/plug was taken out of the circuit? (Ground the PTT pin >without wiring the PTT terminal at the jack.) > >Or > >Is the circuit needed to activate the headset mic? If so, what activates >the mic when you are just using the intercom function? no, you can totally remote the ptt wiring. HOWEVER, it is my personal preference to always wire the mic jack so that the transmitter will function with any standard aviation microphone plugged in. I carry a standard hand mic just in case something comes unhooked in my headset or other parts of ship's wiring. Bob . . .


    Message 16


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    Time: 07:54:12 AM PST US
    From: "Vincent Welch" <welchvincent@hotmail.com>
    Subject: Re: Tach P-lead feed
    --> AeroElectric-List message posted by: "Vincent Welch" <welchvincent@hotmail.com> I have an EIS4000 and would like to go this route. I called Grand Rapids and Greg is out for a week and the lady that answered the phone has no idea what I am talking about. I am using one impulse coupled mag and one Lightspeed ignition. Have any of you guys hooked up the EIS with Van's tach transducer, and if so, would you mind sharing your methods? Thanks Vince Welch >From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> >Reply-To: aeroelectric-list@matronics.com >To: aeroelectric-list@matronics.com >Subject: Re: AeroElectric-List: Tach P-lead feed >Date: Mon, 12 May 2003 23:41:16 -0500 > >--> AeroElectric-List message posted by: "Robert L. Nuckolls, III" ><bob.nuckolls@cox.net> > >At 10:32 PM 5/12/2003 -0500, you wrote: > >--> AeroElectric-List message posted by: Charles Brame > ><charleyb@earthlink.net> > > > >As I understand it, a tach feed from a mag P-lead will work regardless > >of whether the mag is "On" or "Off." A mag is turned "Off" by grounding > >it, so the P-lead connection at the mag should continue to provide tach > >info. The only problem (according to the VM-1000 folks) is that there > >may be minor erratic tach indications if the mag has an impulse starter. > > Don't think so. A mag driven tach looks for the "low" > voltage mirror image of the spark that appears across OPEN > points of the mag switch. Closed switch, no spark, no signal > to tach. > > > >I'm not flying yet, so I cannot confirm. Maybe Bob can confirm. > > > >Another option is a transducer that fits on the mechanical tach port on > >a Lycoming. Van sells the transducer for $60 (part #IE VTACHGEN2) or $67 > >if you have a vacuum pump (part #IE VTACGEN12.) > > This is the very best way to go. Bypass the ignition systems > entirely. I designed tach transducers for the Bonanzas and Barons > when they went to 2" instruments back in the 80's . . . built > a hall effect transducer that screwed right onto the tach drive > fitting of the engine. > > Bob . . . > >


    Message 17


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    Time: 08:37:22 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: AutoPilot Disconnect
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 10:00 AM 5/13/2003 -0400, you wrote: >--> AeroElectric-List message posted by: "Shannon Knoepflein" ><kycshann@kyol.net> > >The diode will be ineffectual because of the latch in resistor. This >resistor will provide a means of dissipating the coils field current. that's true if the field collapse current flows through the resistor . . . but consider that during relay drop-out, there's a dead short across it through the dis-engage switch. >Assuming the coil of the s704-1 is about 150 ohms, based on your >statement of less than 100ma to engage, we get 150+10, or 160 ohms >resistance from 14V to ground (once the engage switch is pressed). This >computes to 87.5mA of current flow, hence a 2A switch is more than >enough. The engage current is less than 100mA per the specs of the >s704-1. The disengage current will be 14/10, or 1.4A, still within 2A. > > >We can get by with the 1W resistor due to the current limiting of the >coil resistance to under 100mA (~150 ohms). Adding the 10ohm resistor >lowers the current further to about 87.5mA. The power dissipated in the >resistor is I >2*R, or 87.5mA >2*10= 0.076W, well under the 1W rating. Actually, power limiting in the resistor is more a function of the TIME that major currents flow. During engage, resistor current flows for the 5 milliseconds of relay pull-in time, and 2 milliseconds or so of drop-out time during dis-engage. So actually, a 1/2w resistor would work nicely too. There's another simple circuit that uses an SCR as the latching device such that the engage/disengage switch never sees load current . . . but this circuit needs more parts too. I was thumbing through an old notebook and found this idea recorded from a project I worked on quite some time ago. It was so much simpler than the diagram I published last year, I decided to update the published drawing. By the way, one can make this a multi-pole relay and run trim motors through their own circuits as well. This is what would be done on an airplane like a bizjet. One button disconnects all motors that drive flight surfaces. Bob . . .


    Message 18


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    Time: 08:41:21 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: OV circuit breaker tripping
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> > >Bob- >After disconnecting the ov module and doing the above, the circuit breaker >stays in for about 8 seconds and then trips. Interestingly, when the >circuit breaker is in, the voltmeter only reads 12.0 volts. Do you have any >idea what could be wrong? As I said originally, the alternator is a brand >new, out of the box, internally regulated 12V variety. > >John Karnes Has this system ever worked for a period of time? I presume that you're doing this test with the engine running and the constant indication of 12v suggests that the alternator is not becoming active at any level. I'd check over the wiring. Try closing the alternator control switch with the engine not running. You should hear the alternator disconnect contactor operate and the breaker should stay in. Sounds like a possible wiring problem. Bob . . .


    Message 19


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    Time: 09:01:24 AM PST US
    From: "Phil Birkelbach" <phil@petrasoft.net>
    Subject: Re: Flap system failure modes (Was circuit protection
    issues) --> AeroElectric-List message posted by: "Phil Birkelbach" <phil@petrasoft.net> > Giles sent me the following photo: > http://216.55.140.222/temp/flap_drive.jpg > > Let's fully explore whether or not you really > want to put this system into your airplane. Then > let's see if there are some simpler yet practical > approaches to keeping working motors powered and > smoke inside the wires. > > I'm convinced that we're just spinning our > wheels on the electrical side until we have > some confidence on how the mechanical side is > going to work and how it behaves when it's > not working. > I have to agree with Bob. I think that I would SERIOUSLY explore the reasons why there are four motors in this system. It will NOT increase the reliability of this system. Especially with the worm gears. I suspect that those worm gears have a fairly high turn down and the higher the turn down on a worm gear the higher the braking action. Try to get one set of these motors to turn with only one motor wired up. If they won't do it then I'd send the whole thing back to whomever built it and design/buy a system that uses one motor. There may be a ratchet type clutch in there somewhere that would allow for the flaps to at least be retracted once if something broke but then you would not be able to extend them. Depending on the airplane this may be acceptable. Get us some more information about this system and what problems were associated with the design of the system. Did they need more torque? Is there a space constraint? Did they assume that more motors would be more reliable? Sometimes in a design of a system like this there are problems that surface that initiate a solution that unknowingly creates other problems. It happens to me at work all the time, I get started down a path to solve one little problem and it is hard to disassociate myself from that small problem so I don't see the bigger problem that my solution created until later. This is where a second, third, or fourth set of eyes can really help. Godspeed, Phil Birkelbach RV7 - 727WB (Reserved) http://www.myrv7.com


    Message 20


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    Time: 09:55:35 AM PST US
    From: "Shannon Knoepflein" <kycshann@kyol.net>
    Subject: AutoPilot Disconnect
    --> AeroElectric-List message posted by: "Shannon Knoepflein" <kycshann@kyol.net> Dissipation in resistor at time of disengage is (14-0)/10, or 1.4A, or 19.6W. It lasts about 2ms from your post. However, there is a way to calculate it based on the R and L values. There is some time constant. For an RC circuit, its 1/RC. If I recall correctly, for an RL, it would be L/R. Close? If that's correct, does the coil have an inductance of about 0.32H, assuming R is 150 + 10=160? --- Shannon Knoepflein <---> kycshann@kyol.net Okay, what is the dissipation in resistor at time of dis-engage switch closure and how long does it last? What is dissipation mode for energy stored in the relay coil? >(is there a prize????) ;-) -john- Sure, after you finish the test . . . Bob . . .


    Message 21


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    Time: 10:09:33 AM PST US
    From: MikeM <mladejov@ced.utah.edu>
    Subject: Re: AutoPilot Disconnect Brain Teaser - 05/12/03
    --> AeroElectric-List message posted by: MikeM <mladejov@ced.utah.edu> With reference to: > http://216.55.140.222/temp/AP_Disconnect_B.pdf > > Here's a brain teaser for you electro-wienies out there. Oh Goody, a pop quiz like the ones I spring on my students! > Why is a diode across the coil of the relay not only > not needed but would be ineffectual were it included? A snubber diode is not required because as the switch is moved to the "disengage" position, it is shorting the relay coil, and thereby provides a path for the coil current to continue flowing while the energy stored in the magnetic field is dissipated in the coil resistance. The closed switch contact effectively holds the coil voltage at 0 V, so absent a forward bias, a diode would do nothing! > Why, if we can hook an autopilot motor of up to 5A > on this disconnect system, an itty-bitty stick-grip > engage/disengage switch good for perhaps 2A is sufficient? While the switch is held in the "engage" position, the relay coil resistance limits the current through the switch to E/R=14/120=0.12A. On "disengage", the peak current is E/R=14/10=1.4A, but lasts only while the relay magnetic field collapses and the relay contacts release. If an external current path is provided (in this case through the switch), a relay like this typically releases in about 10msec. > Why can we get by with a 1w resistor when dissipation > in this resistor at 14v is nearly 20 watts? Even though the peak instantaneous dissipation in the resistor is E 2/R=14*14/10=19.6W, the event lasts only for ~10 msec. A 1W resistor will take 20W for 10msec provided it only happens occasionally. I'm guessing that a 1/4 or 1/2 W resistor would be sufficient. Proff. Mike Mladejovsky, PhDEE (penultimate electro wienie) Skylane '1MM Pacer '00Z


    Message 22


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    Time: 10:32:57 AM PST US
    From: John Loram <johnl@loram.org>
    Subject: AutoPilot Disconnect
    --> AeroElectric-List message posted by: John Loram <johnl@loram.org> At 10:01 PM 5/12/2003 -0700, you wrote: >--> AeroElectric-List message posted by: John Loram <johnl@loram.org> > >This is fun; > >The first thing to know is that the relay's coil (S704-1) has a resistance >of greater than 140 ohms (base on Aeroelectric specs of, "coil current is >under 100 millamps [sic]"). yes >In the 'quiescent' state (no servo motor power) there is no current flowing >through either the coil or the resistor. yes >In the 'active' state (servo motor is powered) there is 14 volts to the top >of the 10 ohm resistor which flows through the resistor and the relay coil >to ground. This current is sufficient to hold the relay in the active >position, and is 14volts / (10 ohms + 140 ohms) = .092 amps (92 milliamps). >This produces .092ma >2 * 140ohms = 1.18 watts dissipation in the relay (it >will run warm) and .092ma >2 * 10 = 0.08 watts dissipation in the resistor. yes >During the transition state when the small switch is held in the 'engage' >position, 14 volts is applied directly across the relay coil, pulling the >relay into the 'active' state. yes, but assume you have a 5A load (2.5 ohms) load (servo motor) what is dissipation in resistor at time of engage switch closure and how long does it last? Yeh, I should have said something about that. At the time I didn't know anything about the servo motor's electrical characteristics so left the answer incomplete; There will be a current surge through the resistor and small switch of 14volts/(1/(1/10+1/2.5)) = 2amps (plus 100 milliamps through the relay coil or 1.4 watts in the resistor. It will last unit the relay pulls into the active state (a few milliseconds at worst) at which time the current through the small switch will drop to 100 milliamps (coil current) until the small switch is opened. >During the transition state when the small switch is held in the 'disengage' >position, the junction between the 10 ohm resistor and the relay coil will >be held at ground. The current (92 milliamps) flowing through the relay coil >will flow through the small switch to ground, and the energy stored in the >relay coil's magnetic field will be dissipated in the coil's resistance. >There will be a brief spike of current (a bit over an amp) from the 10 ohm >resistor through the small switch. This current will stop as soon as the >relay's magnetic field falls to the point where the relay contacts open >(drops out). Okay, what is the dissipation in resistor at time of dis-engage switch closure and how long does it last? There will be a brief surge of current through the switch at disengage time which will be the sum of the current through the resistor (14 volts / 10 ohms = 1.4 amps (19.6watts )(I'm assuming for simplicity that the servo motor is purely resistive) and the coil current .092 milliamps. The current through the resistor will continue until the magnetic field in the relay collapses to the point at which the relay drops out (usually several milliseconds). What is dissipation mode for energy stored in the relay coil? The energy stored in the relay coil's magnetic field will be dissipated in the coil's resistance as the current circulates, primarily through the small switch. This analysis makes some simplifying assumptions; most importantly that the switch and relay contacts have zero resistance, and that the only non-purely resistive component is the relay coil. The calculation of the effect of these tertiary elements are left to the student.... ;-) >(is there a prize????) ;-) -john- Sure, after you finish the test . . . Bob . . .


    Message 23


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    Time: 11:28:37 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: AutoPilot Disconnect Brain Teaser -
    05/12/03 --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 11:06 AM 5/13/2003 -0600, you wrote: >--> AeroElectric-List message posted by: MikeM <mladejov@ced.utah.edu> > >With reference to: > > > http://216.55.140.222/temp/AP_Disconnect_B.pdf > > > > Here's a brain teaser for you electro-wienies out there. > >Oh Goody, a pop quiz like the ones I spring on my students! > <snip> >Even though the peak instantaneous dissipation in the resistor >is E >2/R=14*14/10=19.6W, the event lasts only for ~10 msec. A 1W >resistor will take 20W for 10msec provided it only happens >occasionally. I'm guessing that a 1/4 or 1/2 W resistor would be >sufficient. > >Proff. Mike Mladejovsky, PhDEE (penultimate electro wienie) >Skylane '1MM >Pacer '00Z You got it. If you like good illustrative brain teasers, try these on the class . . . Take molecules of water in 1 cc and enlarge to size of ping-pong ball (assume 1.5" diameter). Spread them uniformly over surface of contiguous US (assume) 5.7 x 10 6 square miles. To what depth will the ping-pong balls cover the United States? Another eye-opener . . . Take an array of steel balls 0.001" in diameter and stack them into 1 cubic inch of volume. How many balls does it take to fill the cube? What is the total surface area of all balls contained in the cube? What is the open (see-through) area of the space between the balls for any liquid that passes into one face and out the opposite face? Bob . . .


    Message 24


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    Time: 11:34:04 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: AutoPilot Disconnect
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 12:52 PM 5/13/2003 -0400, you wrote: >--> AeroElectric-List message posted by: "Shannon Knoepflein" ><kycshann@kyol.net> > >Dissipation in resistor at time of disengage is (14-0)/10, or 1.4A, or >19.6W. It lasts about 2ms from your post. However, there is a way to >calculate it based on the R and L values. > >There is some time constant. For an RC circuit, its 1/RC. If I recall >correctly, for an RL, it would be L/R. Close? If that's correct, does >the coil have an inductance of about 0.32H, assuming R is 150 + 10=160? You're correct that there are other relationships to consider but in comparison to the major effects, they are pretty small and I was neglecting them. The major effects for what the resistor sees have more to do with Bus, Load and engage/disengage switch. For example, you could substitute a 160 ohm resistor for the effects of the relay coil and not significantly change the outcome of the analysis. Bob . . .


    Message 25


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    Time: 11:43:25 AM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: OV runaway in an internally regulated alternator
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 06:01 PM 5/13/2003 +0000, you wrote: >Below is the result of your inquiry. It was submitted by >Frank Piszkin (fpiszkin@thegrid.net) on Tuesday, May 13, 2003 at 11:01:57 > >Tuesday, May 13, 2003 > >Frank Piszkin > >, >Email: fpiszkin@thegrid.net >Comments/Questions: I submitted this inquiry a couple of weeks ago but >have received no response. >So, again, can you help me understand how the alternator disconnect contactor >(S701-1) effects a disconnect? My electrical knowledge is barely beyond Ohm's >Law. Looking at the wiring diagram you provided (for the internal regulator), >it appears to me that the OVM-14 module is required to drop out the field >voltage >to the alternator (and the contactor) and cause the contactor to disconnect. >But there is a jumper wire on the contactor which would appear to hold in >the contactor since it provides a path to the battery side. What am I >misunderstanding? >And, why is the disconnect contactor required if the OVM-14 would, by itself, >remove the field voltage from the alternator? Is it just simply to assure >isolation >of the aternator from the battery side? Please dumb it down for me, Bob. I >really do >want to understand how the system functions before I go wiring things up. >Thanks, Frank I think I invited you to join the AeroElectric List for this conversation. I get lots of requests for one-on-one tutorials every week and I've got a limited amount of time to devote to operating the 'Connection. When you put these questions out on the list, you're more likely to get a response from me because (1) I've blocked out most of my time to support the list and (2) the information is shared with lots of other folks. Moreover, there are many folks on the list besides me who can do a good job of answering. Not trying to be a hard-ass. Further, I very much appreciate and encourage your desire to understand how the system works. I firmly belive in the dissemination of knowledge. But this activity works 1000% better in a forum where many can benefit both as students and as teachers. In a nutshell . . . internally regulated alternators do not get their field excitation current from the control lead. There are failure modes within an internally regulated alternator that cannot be overridden by shutting off the control lead. Hence, the need for physical and total disconnection of the alternator from ship's wiring in the event of an overvoltage event. Bob . . . |---------------------------------------------------| | A lie can travel half way around the world while | | the truth is till putting on its shoes . . . | | -Mark Twain- | |---------------------------------------------------|


    Message 26


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    Time: 12:05:53 PM PST US
    From: "JOHN KARNES" <jpkarnes@charter.net>
    Subject: Re: OV circuit breaker tripping
    --> AeroElectric-List message posted by: "JOHN KARNES" <jpkarnes@charter.net> > Has this system ever worked for a period of time? I >presume > that you're doing this test with the engine running >and the > constant indication of 12v suggests that the >alternator is > not becoming active at any level. I'd check over the >wiring. > Try closing the alternator control switch with the >engine not > running. You should hear the alternator disconnect >contactor > operate and the breaker should stay in. > > Sounds like a possible wiring problem. > > Bob . . . Bob- The system worked fine as currently wired until my engine overheated last summer. The old alternator had bad diodes, so I thought that was the problem. After replacing the OV module and alternator, the problem continues. Why would the circuit breaker trip if there is only 12V leaving the alternator? When the button is pushed in on the circuit breaker, there is a small rise in voltage, albeit only to 12.0 V. If there is a wiring problem, where would you suggest I look? Thanks for your help John Karnes jpkarnes@charter.net


    Message 27


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    Time: 12:06:41 PM PST US
    From: "Gilles.Thesee" <Gilles.Thesee@ac-grenoble.fr>
    Subject: Re: Flap system failure modes (Was circuit protection
    issues) --> AeroElectric-List message posted by: "Gilles.Thesee" <Gilles.Thesee@ac-grenoble.fr> Hi Bob and all, > It sounds to me like your airplane has flaps capable of > defining a high-risk envelope that you want to avoid by > NOT extending flaps beyond a value that you can arrest > decent until your comfortable landing is assured. This > has nothing to do with flap extension/retraction reliability. > Suggest you fully explore this with someone very familiar > with your airplane or experienced enough as a test pilot > to help you put bounds on operating conditions. > This has been recognized by the kit manufacturer, who proposes to reduce flap extension to less drastic values. By the way the test pilot is my former chief pilot and aerobatics coach. > > I think I disagree. Looking at the picture you sent I > perceive that the motors drive a common shaft though worm > gear drives. Worm gears are horribly inefficient . . . usually > 50% or less. They can produce tremendous mechanical > advantage in one gear-pass . . . that's why they are popular. > Their ability to resist back driving due to horrible efficiency > is sometimes RELIED upon . . . > .................... > > I presume that four motors were put into this system because > someone perceived that this much horsepower was needed -OR- > they thought that even if only two motors were needed to > run the flaps, dual motors would give some degree of reliability > enhancement. > > I am skeptical that this 4-motor system would still be okay > with one motor inoperative but mechanically free. If one motor > throws a comm bar or winding and locks up, then the system > is definitely in trouble. > ................ > > I'm convinced that we're just spinning our > wheels on the electrical side until we have > some confidence on how the mechanical side is > going to work and how it behaves when it's > not working. Please tell me if I understand correctly : the flap system could very well lock up in case of motor failure. Provided I have to wire the system as is, I have to make provision for an electrically safe behaviour in this case. The resettable breaker is out of the question, any resetting could induce wire overheating, or asymetrical deployment. > Has this system flown? The system is flying in about 40 to 50 two seaters and five or so four seaters. The only failures I'm aware of are smoke under the panel on the ground, and failure to extend due to loose connections. Has it been tested for all > failure modes including passive failure of one motor > and hard failure (locked armature) of one motor? > I guess you and I know too well.... > > That bar on the floor for manual flap operation is pretty > hard to beat too. My recommendations for wiring and > protection may indeed keep your wires from catching fire > . . . but given the questions I've cited above, your > biggest concerns may have nothing to do with keeping the > smoke in your wires. You're right. Hand flaps are among the safest. But such a system would entail extensive mods of the fuselage, console and throttle, wire conduits etc... Unfortunately the decisions have been made last year, and I'm not in a position to decide on a major redesign of the mechanical systems. I'm only in charge of the wiring, but I'm determined to accomplish it as best as I can, and thanks to your advice, to make it as ELECTRICALLY safe as is practically possible. That's why I was thinking of a fuselink to replace the fast acting fuse. Doable, not doable ? > > I forget now, which airplane are you building? It is an MCR 4S, see http://www.avnet.co.uk/touchdown/pages/mcr4s.htm Thanks for all your help.


    Message 28


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    Time: 12:06:41 PM PST US
    From: "Gilles.Thesee" <Gilles.Thesee@ac-grenoble.fr>
    Subject: Re: Flap system failure modes (Was circuit protection
    issues) --> AeroElectric-List message posted by: "Gilles.Thesee" <Gilles.Thesee@ac-grenoble.fr> Phil, > > I have to agree with Bob. I think that I would SERIOUSLY explore the > reasons why there are four motors in this system. It will NOT increase the > reliability of this system. Especially with the worm gears. I suspect that > those worm gears have a fairly high turn down and the higher the turn down > on a worm gear the higher the braking action. Try to get one set of these > motors to turn with only one motor wired up. If they won't do it then I'd > send the whole thing back to whomever built it and design/buy a system that > uses one motor. If it were my airplane, I would'nt even bother to make this experiment : I'd design something else from the start. But I'm NOT the one who makes the decisions on that project. I definitely am the one in charge of making those motors spin as long as they don't fall apart or weld solid inside, and keeping the smoke inside the wires. > > There may be a ratchet type clutch in there somewhere that would allow for > the flaps to at least be retracted once if something broke but then you > would not be able to extend them. Depending on the airplane this may be > acceptable. > > Get us some more information about this system and what problems were > associated with the design of the system. Did they need more torque? Sure Is > there a space constraint? No Did they assume that more motors would be more > reliable? Don't think so. Torque. And being acqainted with the motor for already using it for the pitch trim. Sometimes in a design of a system like this there are problems > that surface that initiate a solution that unknowingly creates other > problems. It happens to me at work all the time, I get started down a path > to solve one little problem and it is hard to disassociate myself from that > small problem so I don't see the bigger problem that my solution created > until later. This is where a second, third, or fourth set of eyes can > really help. > See my other mail. thanks for your advice, Gilles


    Message 29


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    Time: 01:03:51 PM PST US
    From: "Shaun Simpkins" <shauns@hevanet.com>
    Subject: Re: Z13 and Dual Electronic Ignitions
    --> AeroElectric-List message posted by: "Shaun Simpkins" <shauns@hevanet.com> >. . . hmmm . . . maybe that's IT! > [Cirrus] may be selling airplanes with flooded batteries >that cost a lot and they assume the owner is going to > leave it in place for a long time . >Bob . . . Bob: Thanks. I think that's the reason. The prime battery is up front, the secondary battery is buried behind the rear seat, where the owner will forget about it until it's too late. The diode connection from the primary to the secondary alternator system suggests that Cirrus expects the secondary battery to be forgotten; if it dies, they're counting on the primary system to take over. Which says their e-bus is really the primary system, and...ecch. Shaun


    Message 30


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    Time: 01:05:25 PM PST US
    From: "Cy Galley" <cgalley@qcbc.org>
    Subject: Re: OV circuit breaker tripping
    --> AeroElectric-List message posted by: "Cy Galley" <cgalley@qcbc.org> Sounds like a dead short. It would pull down the voltage and the excess amperage would trip the breaker. Cy Galley, TC - Chair, Emergency Aircraft Repair, Oshkosh Editor, EAA Safety Programs cgalley@qcbc.org or experimenter@eaa.org Always looking for articles for the Experimenter ----- Original Message ----- From: "JOHN KARNES" <jpkarnes@charter.net> Subject: Re: AeroElectric-List: OV circuit breaker tripping > --> AeroElectric-List message posted by: "JOHN KARNES" <jpkarnes@charter.net> > > > Has this system ever worked for a period of time? I > >presume > > that you're doing this test with the engine running > >and the > > constant indication of 12v suggests that the > >alternator is > > not becoming active at any level. I'd check over the > >wiring. > > Try closing the alternator control switch with the > >engine not > > running. You should hear the alternator disconnect > >contactor > > operate and the breaker should stay in. > > > > Sounds like a possible wiring problem. > > > > Bob . . . > > > Bob- > The system worked fine as currently wired until my engine > overheated last summer. The old alternator had bad > diodes, so I thought that was the problem. After > replacing the OV module and alternator, the problem > continues. Why would the circuit breaker trip if there is > only 12V leaving the alternator? When the button is > pushed in on the circuit breaker, there is a small rise in > voltage, albeit only to 12.0 V. If there is a wiring > problem, where would you suggest I look? Thanks for your > help > > John Karnes > jpkarnes@charter.net > >


    Message 31


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    Time: 01:13:21 PM PST US
    From: "Phil Birkelbach" <phil@petrasoft.net>
    Subject: Re: AutoPilot Disconnect Brain Teaser - 05/12/03
    --> AeroElectric-List message posted by: "Phil Birkelbach" <phil@petrasoft.net> > Take an array of steel balls 0.001" in diameter > and stack them into 1 cubic inch of volume. How > many balls does it take to fill the cube? What > is the total surface area of all balls contained > in the cube? What is the open (see-through) area > of the space between the balls for any liquid > that passes into one face and out the opposite face? > > Bob . . . > You'll need 1,000 3 steel balls or... 1,000,000,000 balls The surface area of a sphere is... 4*pi*r 2 So the area of one ball... 3.141592E-6 sq in So the area of a billion balls... 3,141.5 sq in or 21.8166 sq ft which is about 2/3 the area of a piece of plywood. Now for the second part the wetted area... It would be 1 sq in - the area of a million circles... area of a circle = pi * r 2 Area of a 0.001" diameter circle = 7.85398E-7 sq in Area of a million of them would be... 0.785398 sq in so the see through area would be... 0.214602 sq in Of course this all assumes that we stack the balls in a rectangular pattern 1,000 balls to an edge, and the 1 cubic inch volume is a 1" x 1" x 1" cube, if it is anything more sinister than that then I don't have time to look it up. :-) Godspeed, Phil Birkelbach - Houston Texas RV-7 N727WB (Reserved) - Fuselage http://www.myrv7.com


    Message 32


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    Time: 03:49:10 PM PST US
    From: Robert McCallum <robert.mccallum2@sympatico.ca>
    Subject: Re: AutoPilot Disconnect Brain Teaser -05/12/03
    --> AeroElectric-List message posted by: Robert McCallum <robert.mccallum2@sympatico.ca> "Robert L. Nuckolls, III" wrote: > --> > > Another eye-opener . . . > > Take an array of steel balls 0.001" in diameter > and stack them into 1 cubic inch of volume. How > many balls does it take to fill the cube? What > is the total surface area of all balls contained > in the cube? What is the open (see-through) area > of the space between the balls for any liquid > that passes into one face and out the opposite face? > > Bob . . . > 1,000,000,000 balls (1 billion) 2,000,000 square inches (.318845 acres) .21461 square inches of open area (just shy of 1/4 of the total area) -- Bob McC DO NOT ARCHIVE


    Message 33


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    Time: 04:33:20 PM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: Flap system failure modes (Was
    circuit protection issues) --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 08:48 PM 5/13/2003 +0200, you wrote: >--> AeroElectric-List message posted by: "Gilles.Thesee" ><Gilles.Thesee@ac-grenoble.fr> > > >Hi Bob and all, > > > > It sounds to me like your airplane has flaps capable of > > defining a high-risk envelope that you want to avoid by > > NOT extending flaps beyond a value that you can arrest > > decent until your comfortable landing is assured. This > > has nothing to do with flap extension/retraction reliability. > > Suggest you fully explore this with someone very familiar > > with your airplane or experienced enough as a test pilot > > to help you put bounds on operating conditions. > > > >This has been recognized by the kit manufacturer, who proposes to reduce >flap extension to less drastic values. By the way the test pilot is my >former chief pilot and aerobatics coach. Okay. I'm not sure you need to have an on-purpose limitation to the flaps as long as your pilots are aware how to use them safely. Benefits of flaps happen at touchdown. More flaps just makes you come down faster and leaves you with less energy to squander in the flare. If I were a flight instructor, I'd not let a student use flaps at all until they were proficient without them. In the older C-150's, you could get the best of both worlds by hanging out no more drag than you can tolerate at full throttle to arrest your descent. When you're sure you have the landing made, put out the rest of the flaps. >Please tell me if I understand correctly : the flap system could very well >lock up in case of motor failure. Provided I have to wire the system as is, >I have to make provision for an electrically safe behaviour in this case. >The resettable breaker is out of the question, any resetting could induce >wire overheating, or asymetrical deployment. This is a distinct possibility. > > Has this system flown? > >The system is flying in about 40 to 50 two seaters and five or so four >seaters. The only failures I'm aware of are smoke under the panel on the >ground, and failure to extend due to loose connections. > > > Has it been tested for all > > failure modes including passive failure of one motor > > and hard failure (locked armature) of one motor? > > > >I guess you and I know too well.... Okay, let's see what we can do to make failures as tolerant as possible. I think I'd simply wire all four motors in parallel with each other. Treat them as a single motor. Drive the system through a single, 20A breaker at the bus. The idea of protecting each motor in any way is scary. You don't want the system to continue to run in any way if one motor has decided to mis-behave. My sense is that this little airplane simply cannot need as much snort as a 20A breaker would suggest. Wire with 14AWG wire and put a 20A breaker in for now. During flight testing, let's put an ammeter in and see what the system REALLY needs. I wouldn't be surprised to see that we can drop the breaker size down to 15 or even 10 amps. An RV actuator runs at under 5A. You don't need to size the breaker for inrush currents. If one wanted to reduce the hazards of single motor failure, we could design some fancy circuitry to sense abnormal operation and shut the whole system down when it was detected. Single point protection combined with judicious use of flaps in approach-to-landing should let you make the best of a rather un-thoughtful design. This wouldn't be the only airplane flying around with idiosyncrasies capable of embarrassing you or driving your pucker factor up. Take a checkout in a Tri-Pacer or a AA-1 Yankee and have the check pilot show you how easy it is to get tense in these airplanes. They ain't your grandfather's C-172. If this system has a satisfactory history . . . meaning that gear-boxes aren't shelling out and motors are hanging in there, then you're not facing gross design limits or high rates of infant mortality. This suggests that until a motor or gearbox reaches wear-out, you won't have to shoulder duties as a failure modes test-pilot soon. Maybe this won't happen until after you've sold the airplane. Bob . . .


    Message 34


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    Time: 04:33:20 PM PST US
    From: Carlos Sa <carlosfsa@yahoo.com>
    Subject: Re: AutoPilot Disconnect Brain Teaser -05/12/03
    --> AeroElectric-List message posted by: Carlos Sa <carlosfsa@yahoo.com> > > Another eye-opener . . . > > > > Take an array of steel balls 0.001" in diameter > > and stack them into 1 cubic inch of volume. How > > many balls does it take to fill the cube? What > > is the total surface area of all balls contained > > in the cube? What is the open (see-through) area > > of the space between the balls for any liquid > > that passes into one face and out the opposite face? > > > > Bob . . . > > > > 1,000,000,000 balls (1 billion) > 2,000,000 square inches (.318845 acres) > .21461 square inches of open area (just shy of 1/4 of the total area) > > -- > Bob McC > DO NOT ARCHIVE Bob, how didja do that? I gave up stacking them at 521,381,234??? :o) Sorry, couldn't resist...


    Message 35


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    Time: 05:11:07 PM PST US
    From: Robert McCallum <robert.mccallum2@sympatico.ca>
    Subject: Re: AutoPilot Disconnect Brain Teaser -05/12/03
    --> AeroElectric-List message posted by: Robert McCallum <robert.mccallum2@sympatico.ca> Carlos Sa wrote: > > Bob, how didja do that? I gave up stacking them at 521,381,234??? :o) > > Sorry, couldn't resist... > Had my assistant (wife) do the second half. -- Bob McC DO NOT ARCHIVE


    Message 36


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    Time: 05:52:01 PM PST US
    From: "nhulin" <nhulin@hotmail.com>
    Subject: Re: Microprocessor based Fuel Gauge Linearizer
    --> AeroElectric-List message posted by: "nhulin" <nhulin@hotmail.com> On Mon May 12 at 7:31 PM Jim Ziegler (jcz@espllc.com) wrote: > I might be interested, do you have a summary of the requirements? Guys, Are you trying to solve a problem here that has limitations that you are unlikely to overcome? I've just installed the fuel tanks in my Zodiac 601XL and have been testing the installation of the VDO style float arm resistive senders. The Zodiac uses tanks of uniform shape but they are installed in a wing with dihedral. Given that the sender is installed in the lower end of the tank to give the best empty reading, the size of the float ball, and the dihedral, I found that for the first few gallons down from full the float ball is pinned to the top of the tank and no meaningful reading can be expected (except, of course, "full"). On the low end it is much better but the ball eventually bottoms before the tank is empty. In the middle it is reasonably linear. For a very unusually shaped tank the linearizer would be helpful. The cost? Perhaps a fuel totalizer would provide more benefit in these cases. Just my 2c. BTW: I designed a simple LED bargraph fuel gauge that seems to work OK (at least in prototype form) since I have four tanks and the cost of gauges was a bit too much. If I'm happy with the design when it is finished I'll let the Aero'List know. ...neil Neil Hulin Zodiac 601XL Cincinnati Ohio


    Message 37


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    Time: 07:48:10 PM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: AutoPilot Disconnect Brain Teaser
    -05/12/03 --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 06:45 PM 5/13/2003 -0400, you wrote: >--> AeroElectric-List message posted by: Robert McCallum ><robert.mccallum2@sympatico.ca> > >"Robert L. Nuckolls, III" wrote: > > > --> > > > > Another eye-opener . . . > > > > Take an array of steel balls 0.001" in diameter > > and stack them into 1 cubic inch of volume. How > > many balls does it take to fill the cube? What > > is the total surface area of all balls contained > > in the cube? What is the open (see-through) area > > of the space between the balls for any liquid > > that passes into one face and out the opposite face? > > > > Bob . . . > > > >1,000,000,000 balls (1 billion) yes >2,000,000 square inches (.318845 acres) ?????? >.21461 square inches of open area (just shy of 1/4 of the total area) yes Bob . . . -------------------------------------------- ( Knowing about a thing is different than ) ( understanding it. One can know a lot ) ( and still understand nothing. ) ( C.F. Kettering ) --------------------------------------------


    Message 38


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    Time: 07:53:12 PM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: AutoPilot Disconnect Brain Teaser -
    05/12/03 --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 03:10 PM 5/13/2003 -0500, you wrote: >--> AeroElectric-List message posted by: "Phil Birkelbach" ><phil@petrasoft.net> > > > Take an array of steel balls 0.001" in diameter > > and stack them into 1 cubic inch of volume. How > > many balls does it take to fill the cube? What > > is the total surface area of all balls contained > > in the cube? What is the open (see-through) area > > of the space between the balls for any liquid > > that passes into one face and out the opposite face? > > > > Bob . . . > > >You'll need 1,000 3 steel balls or... > >1,000,000,000 balls > >The surface area of a sphere is... 4*pi*r 2 > >So the area of one ball... 3.141592E-6 sq in >So the area of a billion balls... 3,141.5 sq in or 21.8166 sq ft >which is about 2/3 the area of a piece of plywood. That's the part that really surprises folks . . . that a 1" cube could have that much surface area contained within. >Now for the second part the wetted area... > >It would be 1 sq in - the area of a million circles... > >area of a circle = pi * r 2 > >Area of a 0.001" diameter circle = 7.85398E-7 sq in >Area of a million of them would be... 0.785398 sq in >so the see through area would be... 0.214602 sq in yup . . . >Of course this all assumes that we stack the balls in a rectangular pattern >1,000 balls to an edge, and the 1 cubic inch volume is a 1" x 1" x 1" cube, >if it is anything more sinister than that then I don't have time to look it >up. :-) yeah, getting all those balls to set in there un-nested takes some REAL patience. Bob . . . -------------------------------------------- ( Knowing about a thing is different than ) ( understanding it. One can know a lot ) ( and still understand nothing. ) ( C.F. Kettering ) --------------------------------------------


    Message 39


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    Time: 07:57:49 PM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: OV circuit breaker tripping
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 03:03 PM 5/13/2003 -0500, you wrote: >--> AeroElectric-List message posted by: "Cy Galley" <cgalley@qcbc.org> > >Sounds like a dead short. >It would pull down the voltage and the excess amperage would trip the >breaker. I agree . . . check to make sure your diode on the b-lead contactor isn't hooked up backwards or shorted. >Cy Galley, TC - Chair, Emergency Aircraft Repair, Oshkosh > >Editor, EAA Safety Programs >cgalley@qcbc.org or experimenter@eaa.org > >Always looking for articles for the Experimenter Cy, Have you picked through the stuff on downloadables section of aeroelectric.com? If there's something you like there, let me know . . . it might need updating. Bob . . .


    Message 40


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    Time: 09:15:09 PM PST US
    From: "John Karnes" <jpkarnes@charter.net>
    Subject: Re: OV circuit breaker tripping
    --> AeroElectric-List message posted by: "John Karnes" <jpkarnes@charter.net> > >Sounds like a dead short. > >It would pull down the voltage and the excess amperage would trip the > >breaker. > > I agree . . . check to make sure your diode on > the b-lead contactor isn't hooked up backwards > or shorted. How do I check to see if the diode is shorted? I know it's not backwards as I haven't changed it and it was working fine before. Could the high heat in the engine compartment have caused this? (I'm talking HIGH heat!) John Karnes


    Message 41


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    Time: 09:15:50 PM PST US
    From: Robert McCallum <robert.mccallum2@sympatico.ca>
    Subject: Re: AutoPilot Disconnect Brain Teaser-05/12/03
    --> AeroElectric-List message posted by: Robert McCallum <robert.mccallum2@sympatico.ca> "Robert L. Nuckolls, III" wrote: > --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> > > > >2,000,000 square inches (.318845 acres) > > ?????? This would be the answer when you are trying to demonstrate your stupidity by leaving out half the formula in the rush to get to the dinner table after being called three times, then not even bothering with a reasonability check before pushing the send button. (feeling a little silly) -- Bob McC DO NOT ARCHIVE


    Message 42


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    Time: 09:24:30 PM PST US
    From: "Rick Fogerson" <rickf@cableone.net>
    Subject: Fw: Electric Bob - Microair Radio-Xpdr Wire Harness
    --> AeroElectric-List message posted by: "Rick Fogerson" <rickf@cableone.net> ----- Original Message ----- From: Rick Fogerson Subject: Microair Radio-Xpdr Wire Harness Hi Bob, Are you going to be selling wiring harness's for the Microair radio or xpdr anytime soon? Rick Fogerson


    Message 43


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    Time: 09:58:27 PM PST US
    From: Geoff Evans <hellothaimassage@yahoo.com>
    Subject: Dual electronic ignition - revisited again
    --> AeroElectric-List message posted by: Geoff Evans <hellothaimassage@yahoo.com> Hi Bob. I thought I was all squared away after our message exchange of a few months ago, but some recent postings of yours on the list have rekindled my confusion. Our prior conversations were about using the Z-13 architecture for dual electronic ignitions, and whether the Z-13 system was any more likely to result in an electrically-caused engine failure (with dual electronic ignitions) than a something like a Z-11 system with an aux battery. At the time, I was confused by some prior postings and some seemingly conflicting language in your book. Basically, my question was this: For an engine with dual electronic ignitions, would I be better off with two batteries and one alternator, or one battery and two alternators (removing all other variables, and assuming the batteries are well-maintained)? You said the following (among other things): Depends on what you choose to worry about. A PROPERLY MAINTAINED RG battery is the single most reliable power source you can put in your airplane. Could you run dual electronic ignition systems from their own fuses on a single battery bus? Sure. Now, what about alternator-out operations. With one alternator and a DESIGN REQUIREMENT that you can exhaust fuel before your battery(ies) run down may suggest some variations on the theme. An AUX battery more than a year old and less than two years old running ONE ignition system says that in the extreme case of running the main battery flat with e-bus loads, the engine keeps running. Alternatively, if you're in a position to get shed of vacuum operated accessories and the pump that drives them, then a second alternator on the vacated vacuum pump pad is a no-brainer decision. Given that (the "no-brainer decision" comment), I was all ready to stick with the Z-13 architecture for a dual electronic ignition engine. Then I read a post of yours last Sunday where you said (in reply to someone else): > > > > I was just amused at your statement on Z-13 because I thought that you > > did not advocate this setup for dual electronic ignition? Correct. Sometimes after a day of brain-wrestling with these things all day at RAC, my thought train gets derailed . . . So, I guess what I'm looking for is some kind of statement akin to one of the following: "We at Aeroelectric Connection do not advocate using the Z-13 architecture for an aircraft with dual electronic ignitions. We prefer dual batteries instead." or... "We at the Aeroelectric Connection believe that the Z-13 architecture does not have any greater chance of total electrical failure than a Z-11 system with an aux battery. In fact, we think it's a better option, and it's perfectly viable for use with dual electronic ignitions." If you'd rather not make either of those statements (for liability reasons, or whatever), I totally understand. I'm just trying to get a feel for your opinion on the matter. Would you personally have any problem getting in an airplane that uses the Z-13 architecture with dual electronic ignitions? I'm trying to avoid the added weight of two full-size batteries, and I really like the idea of having the SD-8 as a backup alternator instead. I'm also trying to avoid the complexity of having a backup battery just for half of a dual ignition system -- if that's even a logical position to take. Can you put an end to the ambiguity (read: my confusion) one and for all? Thanks much! -Geoff RV-8 __________________________________ http://search.yahoo.com


    Message 44


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    Time: 10:03:41 PM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: OV circuit breaker tripping
    --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 09:10 PM 5/13/2003 -0700, you wrote: >--> AeroElectric-List message posted by: "John Karnes" <jpkarnes@charter.net> > > > >Sounds like a dead short. > > >It would pull down the voltage and the excess amperage would trip the > > >breaker. > > > > I agree . . . check to make sure your diode on > > the b-lead contactor isn't hooked up backwards > > or shorted. > >How do I check to see if the diode is shorted? I know it's not backwards as >I haven't changed it and it was working fine before. Use your ohmmeter to check the resistance across the diode. If it (or something else on the line is shorted) it will read very low (less than 1 ohm) no matter which way you attach the leads. > Could the high heat in >the engine compartment have caused this? (I'm talking HIGH heat!) Not likely. Bob . . . -------------------------------------------- ( Knowing about a thing is different than ) ( understanding it. One can know a lot ) ( and still understand nothing. ) ( C.F. Kettering ) --------------------------------------------


    Message 45


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    Time: 10:04:19 PM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: Fw: Electric Bob - Microair Radio-Xpdr
    Wire Harness --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 10:23 PM 5/13/2003 -0600, you wrote: >--> AeroElectric-List message posted by: "Rick Fogerson" <rickf@cableone.net> > > >----- Original Message ----- >From: Rick Fogerson >To: aeroelectric-list@matronics.com >Subject: Microair Radio-Xpdr Wire Harness > > >Hi Bob, >Are you going to be selling wiring harness's for the Microair radio or >xpdr anytime soon? >Rick Fogerson Yes, I need to make some up tomorrow morning. Which ones do you want? Bob . . . -------------------------------------------- ( Knowing about a thing is different than ) ( understanding it. One can know a lot ) ( and still understand nothing. ) ( C.F. Kettering ) --------------------------------------------


    Message 46


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    Time: 10:05:30 PM PST US
    From: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net>
    Subject: Re: AutoPilot Disconnect Brain
    Teaser-05/12/03 --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" <bob.nuckolls@cox.net> At 12:13 AM 5/14/2003 -0400, you wrote: >--> AeroElectric-List message posted by: Robert McCallum ><robert.mccallum2@sympatico.ca> > >"Robert L. Nuckolls, III" wrote: > > > --> AeroElectric-List message posted by: "Robert L. Nuckolls, III" > <bob.nuckolls@cox.net> > > > > > > >2,000,000 square inches (.318845 acres) > > > > ?????? > >This would be the answer when you are trying to demonstrate your stupidity >by leaving out half the >formula in the rush to get to the dinner table after being called three >times, then not even >bothering with a reasonability check before pushing the send button. >(feeling a little silly) Understand . . . I try to limit my silly episodes to one per day. Bob . . .




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