Today's Message Index:
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     1. 08:33 AM - Re: Battery Contactor Voltage Drop (Paul Eckenroth)
     2. 09:03 AM - Re: Battery Contactor Voltage Drop (user9253)
     3. 10:30 AM - Re: Battery Contactor Voltage Drop (Charlie England)
     4. 03:48 PM - Re: Battery Contactor Voltage Drop (Robert L. Nuckolls, III)
     5. 05:30 PM - Re: Battery Contactor Voltage Drop (Paul Eckenroth)
 
 
 
Message 1
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| Subject:  | Re: Battery Contactor Voltage Drop | 
      
      Thanks for the information Charlie.  The reason for the question is that I
      have 1 EFIS each on the regular buss and the E buss which show .9V
      difference.  Does the diode degrade in a way that would increase voltage
      drop.
      
      Paul
      
      
      On Sun, Apr 7, 2019 at 5:34 PM Charlie England <ceengland7@gmail.com> wrote:
      
      > ceengland7@gmail.com>
      >
      > On 4/7/2019 2:16 PM, Paul Eckenroth wrote:
      > > What is the typical voltage drop across the poles of a healthy battery
      > > contactor.  Is there a failure or aging mode where the voltage drop
      > > increases.  How about typical voltage drop across the diode bridge
      > > rectifier for the essential buss.  After eleven trouble free years I
      > > need to sort out some problems with my RV9A.  Thanks for any information.
      > >
      > > Paul
      > Drop across a good contactor should be hard to measure reliably with a
      > regular voltmeter.
      >
      > Drop across a typical silicon diode will be zero with no load, but will
      > be around 0.7V at any significant load.
      > If you have a Schottky diode (not likely, but possible), it will be
      > around 0.5V or less under load.
      >
      > ---
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Message 2
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  | 
      
      
| Subject:  | Re: Battery Contactor Voltage Drop | 
      
      
      Paul,
      The diode is fine.  A voltage drop of 0.9 volts across a diode is normal.  The
      voltage drop depends
       on the diode characteristics and the current.  Some power diodes will drop 1.5
      volts or more.
      
      --------
      Joe Gores
      
      
      Read this topic online here:
      
      http://forums.matronics.com/viewtopic.php?p=488620#488620
      
      
Message 3
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  | 
      
      
| Subject:  | Re: Battery Contactor Voltage Drop | 
      
      As long as the operating voltage with the alternator running is 'normal' 
      (around 14V), I wouldn't be concerned about a 0.9V drop from primary bus 
      across a standard diode block. If the diode is a typical 'full wave 
      rectifier' (square metal or plastic block with 4 leads), and the source 
      is feeding the '-' terminal and the load is on the '+' terminal, the 
      voltage drop will be higher since the path is actually through two 
      diodes in series. Not a big deal as long as you understand what's 
      happening. Only time it might matter is after alternator loss, at the 
      very end of battery life, *if* the E bus is still fed through the diode.
      
      Charlie
      
      On 4/8/2019 10:31 AM, Paul Eckenroth wrote:
      > Thanks for the information Charlie.  The reason for the question is 
      > that I have 1 EFIS each on the regular buss and the E buss which show 
      > .9V difference.  Does the diode degrade in a way that would increase 
      > voltage drop.
      >
      > Paul
      >
      >
      > On Sun, Apr 7, 2019 at 5:34 PM Charlie England <ceengland7@gmail.com 
      > <mailto:ceengland7@gmail.com>> wrote:
      >
      >     <ceengland7@gmail.com <mailto:ceengland7@gmail.com>>
      >
      >     On 4/7/2019 2:16 PM, Paul Eckenroth wrote:
      >     > What is the typical voltage drop across the poles of a healthy
      >     battery
      >     > contactor.  Is there a failure or aging mode where the voltage drop
      >     > increases.  How about typical voltage drop across the diode bridge
      >     > rectifier for the essential buss.  After eleven trouble free
      >     years I
      >     > need to sort out some problems with my RV9A.  Thanks for any
      >     information.
      >     >
      >     > Paul
      >     Drop across a good contactor should be hard to measure reliably
      >     with a
      >     regular voltmeter.
      >
      >     Drop across a typical silicon diode will be zero with no load, but
      >     will
      >     be around 0.7V at any significant load.
      >     If you have a Schottky diode (not likely, but possible), it will be
      >     around 0.5V or less under load.
      >
      >     ---
      >     This email has been checked for viruses by Avast antivirus software.
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Message 4
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  | 
      
      
| Subject:  | Re: Battery Contactor Voltage Drop | 
      
      
      >If the diode is a typical 'full wave rectifier' (square metal or 
      >plastic block with 4 leads), and the source is feeding the '-' 
      >terminal and the load is on the '+' terminal, the voltage drop will 
      >be higher since the path is actually through two diodes in series.
      
         All of my drawings show power input
         on an AC terminal (~) and output
         on the (+). This uses only one of
         the four diodes to minimize voltage
         drop.
      
      >  Not a big deal as long as you understand what's happening. Only 
      > time it might matter is after alternator loss, at the very end of 
      > battery life, *if* the E bus is still fed through the diode.
      
         Correct. Your radios are 'speced' to function
         to 10V or less. By the time a battery gets
         down to 10v (lead acid) or 11.2v (LiFePO4)
         the battery is 'used up'. This is why the
         e-bus alternate feed switch is closed any
         time the alternator is off line . . . which
         lets the electro-whizzies suck the battery
         dry.
      
         Any time the alternator is working, voltage
         drop in the normal feed diode is insignificant.
      
      
         Bob . . . 
      
Message 5
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  | 
      
      
| Subject:  | Re: Battery Contactor Voltage Drop | 
      
      I appreciate everyone's comments.  I thought I had a problem which has now
      evaporated.
      
      Paul
      
      On Mon, Apr 8, 2019 at 6:52 PM Robert L. Nuckolls, III <
      nuckolls.bob@aeroelectric.com> wrote:
      
      > If the diode is a typical 'full wave rectifier' (square metal or plastic
      > block with 4 leads), and the source is feeding the '-' terminal and the
      > load is on the '+' terminal, the voltage drop will be higher since the path
      > is actually through two diodes in series.
      >
      >
      >   All of my drawings show power input
      >   on an AC terminal (~) and output
      >   on the (+). This uses only one of
      >   the four diodes to minimize voltage
      >   drop.
      >
      >  Not a big deal as long as you understand what's happening. Only time it
      > might matter is after alternator loss, at the very end of battery life,
      > *if* the E bus is still fed through the diode.
      >
      >
      >   Correct. Your radios are 'speced' to function
      >   to 10V or less. By the time a battery gets
      >   down to 10v (lead acid) or 11.2v (LiFePO4)
      >   the battery is 'used up'. This is why the
      >   e-bus alternate feed switch is closed any
      >   time the alternator is off line . . . which
      >   lets the electro-whizzies suck the battery
      >   dry.
      >
      >   Any time the alternator is working, voltage
      >   drop in the normal feed diode is insignificant.
      >
      >   Bob . . .
      >
      
 
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