AeroElectric-List Digest Archive

Mon 04/08/19


Total Messages Posted: 5



Today's Message Index:
----------------------
 
     1. 08:33 AM - Re: Battery Contactor Voltage Drop (Paul Eckenroth)
     2. 09:03 AM - Re: Battery Contactor Voltage Drop (user9253)
     3. 10:30 AM - Re: Battery Contactor Voltage Drop (Charlie England)
     4. 03:48 PM - Re: Battery Contactor Voltage Drop (Robert L. Nuckolls, III)
     5. 05:30 PM - Re: Battery Contactor Voltage Drop (Paul Eckenroth)
 
 
 


Message 1


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    Time: 08:33:04 AM PST US
    From: Paul Eckenroth <N509RV@eckenroth.com>
    Subject: Re: Battery Contactor Voltage Drop
    Thanks for the information Charlie. The reason for the question is that I have 1 EFIS each on the regular buss and the E buss which show .9V difference. Does the diode degrade in a way that would increase voltage drop. Paul On Sun, Apr 7, 2019 at 5:34 PM Charlie England <ceengland7@gmail.com> wrote: > ceengland7@gmail.com> > > On 4/7/2019 2:16 PM, Paul Eckenroth wrote: > > What is the typical voltage drop across the poles of a healthy battery > > contactor. Is there a failure or aging mode where the voltage drop > > increases. How about typical voltage drop across the diode bridge > > rectifier for the essential buss. After eleven trouble free years I > > need to sort out some problems with my RV9A. Thanks for any information. > > > > Paul > Drop across a good contactor should be hard to measure reliably with a > regular voltmeter. > > Drop across a typical silicon diode will be zero with no load, but will > be around 0.7V at any significant load. > If you have a Schottky diode (not likely, but possible), it will be > around 0.5V or less under load. > > --- > This email has been checked for viruses by Avast antivirus software. > https://www.avast.com/antivirus > >


    Message 2


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    Time: 09:03:44 AM PST US
    Subject: Re: Battery Contactor Voltage Drop
    From: "user9253" <fransew@gmail.com>
    Paul, The diode is fine. A voltage drop of 0.9 volts across a diode is normal. The voltage drop depends on the diode characteristics and the current. Some power diodes will drop 1.5 volts or more. -------- Joe Gores Read this topic online here: http://forums.matronics.com/viewtopic.php?p=488620#488620


    Message 3


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    Time: 10:30:47 AM PST US
    Subject: Re: Battery Contactor Voltage Drop
    From: Charlie England <ceengland7@gmail.com>
    As long as the operating voltage with the alternator running is 'normal' (around 14V), I wouldn't be concerned about a 0.9V drop from primary bus across a standard diode block. If the diode is a typical 'full wave rectifier' (square metal or plastic block with 4 leads), and the source is feeding the '-' terminal and the load is on the '+' terminal, the voltage drop will be higher since the path is actually through two diodes in series. Not a big deal as long as you understand what's happening. Only time it might matter is after alternator loss, at the very end of battery life, *if* the E bus is still fed through the diode. Charlie On 4/8/2019 10:31 AM, Paul Eckenroth wrote: > Thanks for the information Charlie. The reason for the question is > that I have 1 EFIS each on the regular buss and the E buss which show > .9V difference. Does the diode degrade in a way that would increase > voltage drop. > > Paul > > > On Sun, Apr 7, 2019 at 5:34 PM Charlie England <ceengland7@gmail.com > <mailto:ceengland7@gmail.com>> wrote: > > <ceengland7@gmail.com <mailto:ceengland7@gmail.com>> > > On 4/7/2019 2:16 PM, Paul Eckenroth wrote: > > What is the typical voltage drop across the poles of a healthy > battery > > contactor. Is there a failure or aging mode where the voltage drop > > increases. How about typical voltage drop across the diode bridge > > rectifier for the essential buss. After eleven trouble free > years I > > need to sort out some problems with my RV9A. Thanks for any > information. > > > > Paul > Drop across a good contactor should be hard to measure reliably > with a > regular voltmeter. > > Drop across a typical silicon diode will be zero with no load, but > will > be around 0.7V at any significant load. > If you have a Schottky diode (not likely, but possible), it will be > around 0.5V or less under load. > > --- > This email has been checked for viruses by Avast antivirus software. > https://www.avast.com/antivirus > > ========== > - > Electric-List" rel="noreferrer" > target="_blank">http://www.matronics.com/Navigator?AeroElectric-List > ========== > FORUMS - > eferrer" target="_blank">http://forums.matronics.com > ========== > WIKI - > errer" target="_blank">http://wiki.matronics.com > ========== > b Site - > -Matt Dralle, List Admin. > rel="noreferrer" target="_blank">http://www.matronics.com/contribution > ========== > >


    Message 4


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    Time: 03:48:27 PM PST US
    From: "Robert L. Nuckolls, III" <nuckolls.bob@aeroelectric.com>
    Subject: Re: Battery Contactor Voltage Drop
    >If the diode is a typical 'full wave rectifier' (square metal or >plastic block with 4 leads), and the source is feeding the '-' >terminal and the load is on the '+' terminal, the voltage drop will >be higher since the path is actually through two diodes in series. All of my drawings show power input on an AC terminal (~) and output on the (+). This uses only one of the four diodes to minimize voltage drop. > Not a big deal as long as you understand what's happening. Only > time it might matter is after alternator loss, at the very end of > battery life, *if* the E bus is still fed through the diode. Correct. Your radios are 'speced' to function to 10V or less. By the time a battery gets down to 10v (lead acid) or 11.2v (LiFePO4) the battery is 'used up'. This is why the e-bus alternate feed switch is closed any time the alternator is off line . . . which lets the electro-whizzies suck the battery dry. Any time the alternator is working, voltage drop in the normal feed diode is insignificant. Bob . . .


    Message 5


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    Time: 05:30:30 PM PST US
    From: Paul Eckenroth <N509RV@eckenroth.com>
    Subject: Re: Battery Contactor Voltage Drop
    I appreciate everyone's comments. I thought I had a problem which has now evaporated. Paul On Mon, Apr 8, 2019 at 6:52 PM Robert L. Nuckolls, III < nuckolls.bob@aeroelectric.com> wrote: > If the diode is a typical 'full wave rectifier' (square metal or plastic > block with 4 leads), and the source is feeding the '-' terminal and the > load is on the '+' terminal, the voltage drop will be higher since the path > is actually through two diodes in series. > > > All of my drawings show power input > on an AC terminal (~) and output > on the (+). This uses only one of > the four diodes to minimize voltage > drop. > > Not a big deal as long as you understand what's happening. Only time it > might matter is after alternator loss, at the very end of battery life, > *if* the E bus is still fed through the diode. > > > Correct. Your radios are 'speced' to function > to 10V or less. By the time a battery gets > down to 10v (lead acid) or 11.2v (LiFePO4) > the battery is 'used up'. This is why the > e-bus alternate feed switch is closed any > time the alternator is off line . . . which > lets the electro-whizzies suck the battery > dry. > > Any time the alternator is working, voltage > drop in the normal feed diode is insignificant. > > Bob . . . >




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