Yak-List Digest Archive

Sun 04/25/10


Total Messages Posted: 12



Today's Message Index:
----------------------
 
     1. 03:53 AM - Re: Power (Kevin Kimball)
     2. 04:48 AM - Re: How old is too old? (A. Dennis Savarese)
     3. 05:35 AM - Re: Power (Richard Goode)
     4. 07:59 AM - Re: Power (Fly4fude)
     5. 08:49 AM - Re: Power (psb777)
     6. 09:44 AM - Re: Re: Power (Roger Kemp M.D.)
     7. 09:49 AM - Re: Re: Power (Roger Kemp M.D.)
     8. 01:50 PM - Re: Re: Power (Kevin Kimball)
     9. 02:06 PM - Re: Power (psb777)
    10. 03:58 PM - Re: How old is too old? (keithmckinley)
    11. 03:58 PM - Re: How old is too old? (keithmckinley)
    12. 07:53 PM - Re: Power (N642K)
 
 
 


Message 1


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    Time: 03:53:04 AM PST US
    From: Kevin Kimball <kjkimball@aol.com>
    Subject: Re: Power
    Jim, The short answer to your question is no. A 10% increase in thrust does not directly pair with the same % increase in horsepower. Thrust is a product of torque and it is possible to increase torque without increasing hp the same % as seen in auto engines. A dyno measures torque not horsepower. The hp numbers are derived from the torque readings and then corrected for the conditions at the moment of the run to a standard day. Hp claims should be viewed as advertising and given just such value. For example, there are engine builders who claim 400+ hp from 540 lycomings when in fact, when tested show less hp than engines claiming 330hp. So far with BPE m14p engines, we see about 300# increase in thrust compared to the stock engines. We have a pull test rig here to use for this. This is about 18% increase in thrust from stock while at the same time getting a decrease in head and oil temps, decrease in fuel burn at cruise etc. Sent from my iPhone Kevin On Apr 25, 2010, at 1:34 AM, cjpilot710@aol.com wrote: > > > With a test cell, will be a great asset, practically if it has > something that can accurately measure power. > > Here is a question. I do not have the answer to this and I'm sure I > may be simplifying this big time. > > What if we took (say ) a CJ-6 with a straight M-14p (dymo tested at > 360hp) engine and paddle prop. > We (figuratively) tie it to a tree. Than we run the engine full > power and full rpm. > In the tie down line we have a gage that can measure the pull in > pounds and that pull measured (say) 1,000 lbs. > We than tear down the engine and insert dome pistons. > We than put the engine back on the same airplane and again make a > full power run. > This time the gage in the line reads 1,110 pounds in pull. An > increase of 110 lbs pull. > If we have 1110/1000, I believe we have a 11.1% increase. > If original engine equaled 360hp, would the new configuration equal > 399.96 hp (360+11.1%)? > > BTW I was never known as being particularly astute in math. > > Jim "Pappy" Goolsby > >


    Message 2


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    Time: 04:48:22 AM PST US
    From: "A. Dennis Savarese" <dsavarese0812@bellsouth.net>
    Subject: Re: How old is too old?
    I guess the question is, have you ever seen an airplane fresh from the factory with wrinkles in the fuselage skins? I've always believed they don't build them with wrinkles in the skins. Even the home builts like the RV's don't have wrinkles or ripples in the fuselage skins. Doug may be able to shed some light on the subject. Dennis ----- Original Message ----- From: Pete Fowler To: yak-list@matronics.com Sent: Saturday, April 24, 2010 3:42 PM Subject: Yak-List: How old is too old? While working on my plane at Santa Paula, one of the many A&Ps there happened by and was looking at my fuselage and said "wow, that plane must have been overstressed at some point". We sort of ignored that but since then I've noticed that my fuselage skins are more "wrinkly" from behind the back seat to the tail. Compared to the "Fresh Off Boat" one I saw today, that one had nearly perfectly smooth fuselage skins. My plane is one of the first CJ-6s imported into the U.S. in 1991 and had an estimated 3500 hours when imported so now has something like 4900 hours on the airframe. I know that's nothing compared to most other planes but since it appears to be the (or one of the) highest hour planes around, it made me think. Am I the "guinea pig" for Nanchang hours? How would I determine if the wrinkly skins are "normal"? The local Nanchang guys don't think anything of it but what do you guys think? -------- N4183E http://nanchangcjs.yuku.com/ Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295571#295571


    Message 3


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    Time: 05:35:01 AM PST US
    From: "Richard Goode" <richard.goode@russianaeros.com>
    Subject: Re: Power
    A 10% increase in thrust is a good indicator of 10% more power ,but no more than that. Firstly,a prop will work more or less efficiently at certain powers-for example the V-530 props on Yaks has a problem to transmit more than 350 HP. Seccondly temp.and air pressure are likely to change,and finally,a spring-type of gauge is not very accurate. I go back to my original tennant,and that is,if someone makes any claim about power,or performance [or whatever] it should have been properly measured! Richard Richard Goode Aerobatics Rhodds Farm Lyonshall Hereford HR5 3LW United Kingdom Tel: +44 (0) 1544 340120 Fax: +44 (0) 1544 340129 www.russianaeros.com ----- Original Message ----- From: cjpilot710@aol.com To: yak-list@matronics.com Sent: Sunday, April 25, 2010 6:34 AM Subject: Yak-List: Power With a test cell, will be a great asset, practically if it has something that can accurately measure power. Here is a question. I do not have the answer to this and I'm sure I may be simplifying this big time. What if we took (say ) a CJ-6 with a straight M-14p (dymo tested at 360hp) engine and paddle prop. We (figuratively) tie it to a tree. Than we run the engine full power and full rpm. In the tie down line we have a gage that can measure the pull in pounds and that pull measured (say) 1,000 lbs. We than tear down the engine and insert dome pistons. We than put the engine back on the same airplane and again make a full power run. This time the gage in the line reads 1,110 pounds in pull. An increase of 110 lbs pull. If we have 1110/1000, I believe we have a 11.1% increase. If original engine equaled 360hp, would the new configuration equal 399.96 hp (360+11.1%)? BTW I was never known as being particularly astute in math. Jim "Pappy" Goolsby -------------------------------------------------- This message has been scanned for viruses and dangerous content by the Invictawiz MailScanner and is believed to be clean. http://www.invictawiz.com/ --------------------------------------------------


    Message 4


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    Time: 07:59:16 AM PST US
    Subject: Re: Power
    From: "Fly4fude" <sjdwallace@verizon.net>
    Hi all! I think you all might be making this way too complicated. Bill Blackwell is working on my CJ right now. He assures me you can EASILY get ten (10) EXTRA HORSEPOWER simply by chroming the tail's skid-plate! [Laughing] -------- Scott &quot;Gabby&quot; Wallace Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295632#295632


    Message 5


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    Time: 08:49:59 AM PST US
    Subject: Re: Power
    From: "psb777" <matronics.com@beardsell.com>
    I'm frustrated by repeated attempts here by some to use the terms torque, power and thrust as if they're interchangeable terms, but I'll leave that alone, for the time being at least. Who needs any equipment to measure a power difference? There is a much easier, cheaper, better and much more reliable way of measuring the change in the power produced by an aircraft engine. It doesn't tell you the absolute level of power produced - but it does tell you very accurately the difference in power caused by any engine mod. Accurately measure the rate of climb at a nominated set speed in the aircraft before the mod. Don't use the VSI - there is no reason for these to be calibrated correctly - use the altimeter and a stopwatch. Then do the engine mod and repeat the experiment. We want to keep drag the same so fly the modded a/c at the same speed as before. Assure the a/c has the same weight. Any power difference then goes entirely into providing a different rate of climb. The formula for the power difference is, Pd = m * g * (v2 - v1) where g is acceleration due to gravity, m is the aircraft mass in kg, v1 and v2 are the original and new climb rate in m/s, Pd is the power difference caused by the mod in Watts. Knowing g = 9.81 m/s/s 1 Horsepower is 747 W. 1 m/s = 197 ft/min 1 kg = 2.20 lb then, in old units, m is now the aircraft mass in lb, v1 and v2 are the original and new climb rate but now in feet/min, and Pd is the power difference caused by the mod but now in hp. Pd*747 = m/2.2 * 9.81 * (v2 - v1)/197 or, simplifying, Pd = m * (v2 - v1) / 33100 E.g. An M14P mod is claimed to increase power from 360 to 440hp. Before the mod I climb my 3000lb Yak-18T at 1200ft/min full throttle max-RPM at an exact set speed. After the mod, same atmospheric conditions, *same* speed I can climb at 1400ft/min all levers forward. The power increase is 3000 * (1400 - 1200) / 33100 = 18 hp -------- Paul Beardsell HA-YAB http://beardsell.com/flying/ha-yab Yak-18T http://beardsell.com/flying/yak18t Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295635#295635


    Message 6


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    Time: 09:44:40 AM PST US
    From: "Roger Kemp M.D." <viperdoc@mindspring.com>
    Subject: Re: Power
    Yes and also by using the 18th century medical device known as the medicinal smoke bellows for rectal lavage...aka blowing smoke up ones ass. Doc -----Original Message----- From: owner-yak-list-server@matronics.com [mailto:owner-yak-list-server@matronics.com] On Behalf Of Fly4fude Sent: Sunday, April 25, 2010 9:58 AM Subject: Yak-List: Re: Power Hi all! I think you all might be making this way too complicated. Bill Blackwell is working on my CJ right now. He assures me you can EASILY get ten (10) EXTRA HORSEPOWER simply by chroming the tail's skid-plate! [Laughing] -------- Scott &quot;Gabby&quot; Wallace Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295632#295632


    Message 7


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    Time: 09:49:08 AM PST US
    From: "Roger Kemp M.D." <viperdoc@mindspring.com>
    Subject: Re: Power
    I knew an aeronautical engineer would climb out of the lurking woodwork eventually. Where have you been so long? Thanks for the info. Doc -----Original Message----- From: owner-yak-list-server@matronics.com [mailto:owner-yak-list-server@matronics.com] On Behalf Of psb777 Sent: Sunday, April 25, 2010 10:48 AM Subject: Yak-List: Re: Power I'm frustrated by repeated attempts here by some to use the terms torque, power and thrust as if they're interchangeable terms, but I'll leave that alone, for the time being at least. Who needs any equipment to measure a power difference? There is a much easier, cheaper, better and much more reliable way of measuring the change in the power produced by an aircraft engine. It doesn't tell you the absolute level of power produced - but it does tell you very accurately the difference in power caused by any engine mod. Accurately measure the rate of climb at a nominated set speed in the aircraft before the mod. Don't use the VSI - there is no reason for these to be calibrated correctly - use the altimeter and a stopwatch. Then do the engine mod and repeat the experiment. We want to keep drag the same so fly the modded a/c at the same speed as before. Assure the a/c has the same weight. Any power difference then goes entirely into providing a different rate of climb. The formula for the power difference is, Pd = m * g * (v2 - v1) where g is acceleration due to gravity, m is the aircraft mass in kg, v1 and v2 are the original and new climb rate in m/s, Pd is the power difference caused by the mod in Watts. Knowing g = 9.81 m/s/s 1 Horsepower is 747 W. 1 m/s = 197 ft/min 1 kg = 2.20 lb then, in old units, m is now the aircraft mass in lb, v1 and v2 are the original and new climb rate but now in feet/min, and Pd is the power difference caused by the mod but now in hp. Pd*747 = m/2.2 * 9.81 * (v2 - v1)/197 or, simplifying, Pd = m * (v2 - v1) / 33100 E.g. An M14P mod is claimed to increase power from 360 to 440hp. Before the mod I climb my 3000lb Yak-18T at 1200ft/min full throttle max-RPM at an exact set speed. After the mod, same atmospheric conditions, *same* speed I can climb at 1400ft/min all levers forward. The power increase is 3000 * (1400 - 1200) / 33100 = 18 hp -------- Paul Beardsell HA-YAB http://beardsell.com/flying/ha-yab Yak-18T http://beardsell.com/flying/yak18t Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295635#295635


    Message 8


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    Time: 01:50:09 PM PST US
    From: Kevin Kimball <kjkimball@AOL.COM>
    Subject: Re: Power
    Paul, Cool. So if i understand your example, your aiplane would Need to see 400 fpm increase in roc to 1600 fpm to realize a 10% increase in hp. Likewise, to go from 360 hp to 440 hp as in your example, your airplane would need to see a roc increase of 882 fpm to 2082fpm. That's huge at 73% increase in roc with a 22% increase in hp. Hope my math is ok here Maybe I missed something on these calcs as I am walking through lowes after a day on the lakes. Sent from my iPhone Kevin On Apr 25, 2010, at 11:48 AM, "psb777" <matronics.com@beardsell.com> wrote: > > I'm frustrated by repeated attempts here by some to use > the terms torque, power and thrust as if they're > interchangeable terms, but I'll leave that alone, for the time > being at least. > > Who needs any equipment to measure a power difference? > There is a much easier, cheaper, better and much more > reliable way of measuring the change in the power produced > by an aircraft engine. It doesn't tell you the absolute > level of power produced - but it does tell you very > accurately the difference in power caused by any > engine mod. > > Accurately measure the rate of climb at a > nominated set speed in the aircraft before the mod. > Don't use the VSI - there is no reason for these > to be calibrated correctly - use the altimeter and > a stopwatch. > > Then do the engine mod and repeat the experiment. > We want to keep drag the same so fly the modded a/c > at the same speed as before. Assure the a/c has > the same weight. Any power difference then goes > entirely into providing a different rate of climb. > The formula for the power difference is, > > Pd = m * g * (v2 - v1) > > where > g is acceleration due to gravity, > m is the aircraft mass in kg, > v1 and v2 are the original and new climb rate in m/s, > Pd is the power difference caused by the mod in Watts. > > Knowing > g = 9.81 m/s/s > 1 Horsepower is 747 W. > 1 m/s = 197 ft/min > 1 kg = 2.20 lb > > then, in old units, > m is now the aircraft mass in lb, > v1 and v2 are the original and new climb rate but now in feet/min, and > Pd is the power difference caused by the mod but now in hp. > > Pd*747 = m/2.2 * 9.81 * (v2 - v1)/197 > or, simplifying, > Pd = m * (v2 - v1) / 33100 > > E.g. > > An M14P mod is claimed to increase power from 360 > to 440hp. Before the mod I climb my 3000lb Yak-18T > at 1200ft/min full throttle max-RPM at an exact set > speed. After the mod, same atmospheric conditions, > *same* speed I can climb at 1400ft/min all levers > forward. > > The power increase is > 3000 * (1400 - 1200) / 33100 = 18 hp > > -------- > Paul Beardsell > HA-YAB http://beardsell.com/flying/ha-yab > Yak-18T http://beardsell.com/flying/yak18t > > > Read this topic online here: > > http://forums.matronics.com/viewtopic.php?p=295635#295635 > >


    Message 9


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    Time: 02:06:57 PM PST US
    Subject: Re: Power
    From: "psb777" <matronics.com@beardsell.com>
    All correct except of course my 18T is rarely lighter than 3300 lb or 10% more than I said so its another 10% i.e. not 18hp but 20hp for an extra 200fpm That's the point of course: For any 3300lb plane, with any engine, another 10hp is needed to add another 100fpm to the climb. kjkimball(at)AOL.COM wrote: > Paul, > > Cool. So if i understand your example, your aiplane would > Need to see 400 fpm increase in roc to 1600 fpm to realize a 10% > increase in hp. > > Likewise, to go from 360 hp to 440 hp as in your example, your > airplane would need to see a roc increase of 882 fpm to 2082fpm. > That's huge at 73% increase in roc with a 22% increase in hp. > > Hope my math is ok here Maybe I missed something on these calcs as I > am walking through lowes after a day on the lakes. > > Sent from my iPhone > Kevin > -------- Paul Beardsell HA-YAB http://beardsell.com/flying/ha-yab Yak-18T http://beardsell.com/flying/yak18t Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295667#295667


    Message 10


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    Time: 03:58:16 PM PST US
    Subject: Re: How old is too old?
    From: "keithmckinley" <keith.mckinley@townisp.com>
    how about posting some pictures? -------- Keith McKinley 700HS KFIT Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295684#295684


    Message 11


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    Time: 03:58:28 PM PST US
    Subject: Re: How old is too old?
    From: "keithmckinley" <keith.mckinley@townisp.com>
    how about posting some pictures? -------- Keith McKinley 700HS KFIT Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295685#295685


    Message 12


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    Time: 07:53:29 PM PST US
    Subject: Re: Power
    From: "N642K" <mdecanio@mac.com>
    My two rules: 1. Money spent on the airplane always makes them faster and sexier. 2. Never do math in public. Read this topic online here: http://forums.matronics.com/viewtopic.php?p=295710#295710




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